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ustolemyname
on June 29, 2015
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What is C in practice?
I disagree regarding b. I think you'll find the outcome of this expression quite predictable:
int b; int c = b * 0;
JoshTriplett
on June 29, 2015
[–]
Sure, if the expression doesn't depend on the value at all, it
probably
won't have unpredictable results. (Though as with any kind of undefined behavior, don't count on it, as compilers can be "clever" sometimes.)
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int b; int c = b * 0;